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A force of 70.0 N is exerted at an angle of 30.0° below the horizontal on a block of mass 8.00 kg that is resting on a table. What is the magnitude of the normal force acting on the block?

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The upward component of the 70N force is

70.0N*sinTheta. Add that to the downward component, 8g, and you have the net force downward.

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