A force of 6.2 N applied to the spiral spring of length 9.2 cm causes it to extend by 0.034 m. What is the length of the spiral spring when a force of 4.6 N is applied to it provided the elastic limit is not exceeded?

Answer 1

If just a force of 4.6N, then it extends
4.6/6.2 * 0.034 = ____ cm

If you mean an additional 4.6N, then it extends an additional
(6.2+4.6)/6.2 = ____ cm

Now just add those to the original 9.2 cm length