A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)

Responses

56.1 J
56.1 J

58.4 J
58.4 J

58.1 J
58.1 J

55.8 J

1 answer

The work done (W) on an object can be calculated using the formula:

\[ W = F \times d \]

where:

  • \( F \) is the force applied (in Newtons),
  • \( d \) is the distance over which the force is applied (in meters).

Given:

  • \( F = 57.1 , \text{N} \)
  • \( d = 0.977 , \text{m} \)

Now, substituting the values into the formula:

\[ W = 57.1 , \text{N} \times 0.977 , \text{m} \]

Calculating this:

\[ W = 55.7497 , \text{J} \]

Rounded to one decimal place, the work done is approximately:

\[ W \approx 55.8 , \text{J} \]

Therefore, the correct response is:

55.8 J