A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)

Question

Responses

55.8 J
55.8 J

58.4 J
58.4 J

58.1 J
58.1 J

56.1 J

Answer 1

To calculate the work done on an object, you can use the formula:

$$\text{Work}=\text{Force}\times \text{Distance}\times \cos (\theta )$$

where:

• Work is in joules (J),
• Force is in newtons (N),
• Distance is in meters (m),
• $\theta$ is the angle between the force and the direction of movement.

Assuming the force is applied in the same direction as the movement (which means $\theta =0$ degrees and $\cos (0)=1$), the formula simplifies to:

$$\text{Work}=\text{Force}\times \text{Distance}$$

Substituting the given values:

$$\text{Work}=57.1,\text{N}\times 0.977,\text{m}$$

Calculating this gives:

$$\text{Work}=57.1\times 0.977\approx 55.8,\text{J}$$

So, the work done on the object is approximately 55.8 J.