A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?(1 point)

Responses

56.1 J
56.1 J

58.1 J
58.1 J

58.4 J
58.4 J

55.8 J

1 answer

To calculate the work done on an object, you can use the formula:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

In this case, we are assuming the force is applied in the direction of the motion (which means \(\theta = 0\) degrees, and \(\cos(0) = 1\)). Therefore, the formula simplifies to:

\[ \text{Work} = \text{Force} \times \text{Distance} \]

Given:

  • Force = 57.1 N
  • Distance = 0.977 m

Now, substituting in the values:

\[ \text{Work} = 57.1 , \text{N} \times 0.977 , \text{m} = 55.8507 , \text{J} \]

Rounding to three significant figures, the work done is approximately:

\[ \text{Work} \approx 55.9 , \text{J} \]

Since 55.9 J is not one of your options, the closest response is:

55.8 J.