work=force*distance
Vf^2=2 a *d= 2 (48/2)*3
or Vf=12 m/s
avg velocity= 6m/s
power= force*d/time=force*avg velocity
A force of 48 N pushes a 2 kg object initially at rest a distance of 3m along frictionless horizontally surface. Find:
A- The work done on the object.
B- The power of the applied force.
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