A force of 40.0N is required to pull a 10.0kg wooden block at a constant velocity across a smooth glass surface on Earth. What force would be required to pull the same wooden block across the same glass surface on the planet Jupiter.
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the friction here is 40N, which is directly proportional to weight. What is gravitational force on Jupiter as compared to Earth?
it says to use G=6.670 x 10^-11 Nm^2/kg^2
but that's all the information given
but that's all the information given
Then you will have to look up the mass and radius of Jupiter, OR the ratio of g's on Jupiter and Earth. You don't need to know the value of G.
g = GM/R^2 where M and R are the mass and radius of the body.
g(Jupiter)/g(Earth) = [M(j)/M(e)]*[Re/Rj]^2
g = GM/R^2 where M and R are the mass and radius of the body.
g(Jupiter)/g(Earth) = [M(j)/M(e)]*[Re/Rj]^2
Mass of Jupiter is 1.90x10^27kg
Radius= 7.15x10^7m
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