a force of 4 N acts on a body of mass 2 kg for 4 sec . assuming the body to be initialy at rest . find the distance covered in 10sec after force start acting

Answer 1

d=1/2 a t^2

but a=force/mass
solve so find d for the first 4 seconds, while the object is accelerating.

Then find its velocity at that time..
vf=at

so you now have the distance and velocity after 4 seconds.

The next six seconds, it travels at this velocity d=v*6

add the two distances together.

Answer 2

64m