A force of 2n stretches an elastic materials by 30mm.what additional force will stretch the material 35mm? assume that the elastic limit is not exceeded

Answer 1

To find the additional force required to stretch the material an additional 5mm (from 30mm to 35mm), we can use Hooke's Law, which states that the force required to stretch or compress an elastic material is directly proportional to the amount of stretch or compression.

The formula for Hooke's Law is:

F = k * x

Where:
F = force applied (in newtons)
k = spring constant (in newtons per meter)
x = amount of stretch or compression (in meters)

We are given:
F1 = 2N
x1 = 30mm = 0.03m
x2 = 35mm = 0.035m

Now, we can use the given information to calculate the spring constant (k):

2N = k * 0.03m
k = 2N / 0.03m
k = 66.67 N/m

Now, we can use the spring constant to calculate the additional force required to stretch the material by an additional 5mm:

F2 = k * x2
F2 = 66.67 N/m * 0.035m
F2 = 2.33N

Therefore, an additional force of 2.33N is required to stretch the elastic material by 35mm.