A force of 10N act on a body of mass 5kg for one second than change in momentum is

Answer 1

The change in momentum is given by the formula:

Δp = FΔt

where Δp is the change in momentum, F is the force applied, and Δt is the time for which the force is applied.

In this case, F = 10N and Δt = 1 second. The mass of the body is m = 5kg.

So,

Δp = FΔt

Δp = 10N * 1s

Δp = 10 Ns

Now, using the definition of momentum:

p = mv

where p is momentum, m is mass, and v is velocity.

We can rearrange this formula to find the velocity of the body:

v = p/m

So,

v = Δp/m

v = 10 Ns / 5kg

v = 2 m/s

Therefore, the change in momentum is 10 Ns and the velocity of the body is 2 m/s.