A force of 1.8 N extends a wire by 0.4 cm , what force will extend the wire by 1.25 cm if the elastic limit is not exceeded

Answer 1

To solve this problem, we can use Hooke's Law, which states that the force required to extend or compress a spring is directly proportional to the amount of stretch or compression. The formula for Hooke's Law is:

F = k * x

Where:
F = force applied (unknown)
k = spring constant (unknown)
x = amount of stretch (1.25 cm = 0.0125 m)

We can first find the spring constant, k, using the given information:

1.8 N = k * 0.004 m

k = 1.8 N / 0.004 m
k = 450 N/m

Now, we can use the spring constant to find the force (F) required to extend the wire by 1.25 cm:

F = 450 N/m * 0.0125 m
F = 5.625 N

Therefore, a force of 5.625 N will extend the wire by 1.25 cm without exceeding the elastic limit.