The elastic constant of a spring is given by the formula:
k = F/x
where F is the applied force and x is the resulting elongation or compression of the spring.
In this case, F = 0.8 N and x = 5 cm = 0.05 m.
Thus,
k = F/x = 0.8 N / 0.05 m = 16 N/m
Therefore, the elastic constant of the spring is 16 N/m.
A force of 0.8N stretches an elastic spring by 5cm.cm find the elastic constant of the spring
3 answers
If a force of 100N stretches a spring by 0.1cm,find the elastic constant.
The elastic constant of a spring is given by the formula:
k = F/x
where F is the applied force and x is the resulting elongation or compression of the spring.
In this case, F = 100 N and x = 0.1 cm = 0.001 m.
Thus,
k = F/x = 100 N / 0.001 m = 100,000 N/m
Therefore, the elastic constant of the spring is 100,000 N/m.
k = F/x
where F is the applied force and x is the resulting elongation or compression of the spring.
In this case, F = 100 N and x = 0.1 cm = 0.001 m.
Thus,
k = F/x = 100 N / 0.001 m = 100,000 N/m
Therefore, the elastic constant of the spring is 100,000 N/m.