A force of 0.053 N is required to move a charge of 36 µ a distance of 30 cm in a uniform electric field. What is the size of the electric potential difference between the two points?

Answer 1

F * d = q * V

V = F * d / q

= .053 * .3 /36*10^-6

= 5.3 * 10^-2 * 3 * 10^-1 *10^6/36

= .442 * 10^3

= 442 volts