a force is applied to a body of mass 0.9 kgs that is at rest the force is applied for a duration of 5 sec and as a result the body covers a distance of 250 m find the magnitude of force

Answer 1

since the force applied gives the body kinetic energy from rest:fd=1/2mv^2 d=1/2at^2 250=1/2a(5)(5) a=20m/s^2 since body start from rest u=0:a=v/t 20=v/5 v=100m/s from the equation:f(250)=1/2*0.9*100^2 250F=4500 F=18N