F = 6.90[54o] + 5[90o]
X = 6.9*Cos54 + 5*Cos90 = 4.1 Units.
Y = 6.9*sin54 + 5*sin90 = 10.6 Units.
Q1.
F = sqrt(X^2 + Y^2) = 11.4 Units.
Tan A = Y/X = 10.6/4.1 = 2.58537.
A = 68.9o CCW = Direction.
OR:
Y = F*sin A = 10.6.
sin A = 10.6/F = 10.6/11.4 = 0.92982.
A = 68.4o CCW.
A force F1 of magnitude 6.90 units acts on an object at the origin in a direction θ = 54.0° above the positive x-axis. (See the figure below.) A second force
F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.
I have gotten 11.3 for the magnitude, which is correct, but can not figure out the direction: (counter clockwise from the +x-axis
2 answers
I did the same problem but it was 6.8 units. so .1 less and the 68.4 is the correct one I put in 68.3 and I got it correct so.
1 answer