A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,

Question

calculate the three components of the torque vector ~� = �xˆi + �y ˆj + �z ˆk .
First, calculate the �x component.
Answer in units of Nm

Answer 1

torque about origin

M = R cross F

i j k
x y z
Fx Fy Fz determinant

=(y Fz-z Fy)i+(z Fx-x Fz)j *(x Fy-y Fx)k

so x component
(y Fz-z Fy)
= 1.67*60 - 7.03*7.56
= 47.1 Nm

Answer 2

How do you calculate the �y component.
Answer in units of Nm.
How do you calculate the �z component.
Answer in units of Nm.