The dot product f*d equals 6 Joules, if the force is in Newtons and the displacement distance is in meters.
-12 +2c +6 = 12
2c = 18
Take it from there
a force f= 3i+cj+2k acting on a particle causes displacement , d=-4i+2j+3k.
If the work done is 6 joule then the value of c.
Plz. Solve
2 answers
(3i+cj+2k)(-4i+2j_3k)
= -12i+2cj-6k=6
=-12+2c-6=6
=-12+2c=6+6
=-12+2c=12
=2c=-12 -12
=2c =24
=c=24÷2
=c=12
Therefore, C=12.
= -12i+2cj-6k=6
=-12+2c-6=6
=-12+2c=6+6
=-12+2c=12
=2c=-12 -12
=2c =24
=c=24÷2
=c=12
Therefore, C=12.
2 answers