A force described by F(t) = ½ t2 – 5t acts on an object from t = 0 to t = 3 seconds. The object, which has a mass of 2 kg, is at rest at t = 0. Determine the velocity of the object at t = 3 seconds.

Answer 1

F(t) = 0.5t^2 - 5t = 05*3^2 - 5*3 = 10.5 N.

F = M*a.
a = F/M = 10.5/2 = 5.25 m/s^2.

V = Vo + a*t = 0 + 5.25*3 =