A football player punts the ball at a 45.0o

Question

angle. Without an effect from the wind, the ball would
travel 60.0 m horizontally. (a) What is the initial speed of the ball? (b) When the ball is near its
maximum height it experiences a brief gust of wind that reduces its horizontal velocity by
1.50 m/s. What total distance does the ball travel horizontally?

Answer 1

without wind:

hf=hi+vo*t-1/2 g t^2
hf, hi =0
time t= sqrt(2vSin45)/g)
distance horizontal=vo*cos45*t
60=vo*.707*sqrt(2vo*.707/9.8)
solve for vo.

Then, the wind gust: time in the air is the same, so distance=t/2*vo .707+t/2(vo*.707-1.5)

Answer 2

4.78