A football player of mass 103 kg running with a velocity of 2.0 m/s [E] collides head-on with a 110 kg player on the opposing team travelling with a velocity of 3.2 m/s [W]. Immediately after the collision the two players move in the same direction. Calculate the final velocity of the two players.

Answer 1

M1*V1 + M2*V2 = M1*V + M2*V.
103*2 + 110*(-3.2) = 103V + 110V,
V = -0.685 m/s. = 0.685 m/s West.