a) K.E. = 108 N * 0.3 m = 32.4 J
b) 1/2 m v^2 = 1/2 * .55 kg * v^2 = 32.4 J
... v^2 = 2 * 32.4 / .55 = ? m^2/s^2
A football of mass 550 g is at rest on the ground. The football iskicked with a force of 108 N. The footballer’s boot is in contactwith the ball for 0.3 m.
a)What is the kinetic energy of the ball?
b)What is the ball’s velocity at the moment it loses contact with the footballer’s boot?
3 answers
Thank you
W=324J=KE
W=1/2mv^2
v=√648/550
V=0.046
W=1/2mv^2
v=√648/550
V=0.046