When the ball reaches the highest point, it means that its vertical velocty v1 is zero.
With an initial velocity of v0 (upwards), and an acceleration due to gravity of -g (downwards), we use the relation
v1=v0+at
substituting v1=0, v0=16.5 and g=-9.81, you would be able to solve for t (answer to part a)
The remaining parts can be readily answered knowing t.
A football is thrown with an initial upward velocity component of 13.5m/s and a horizontal velocity component of 16.5m/s
How much time is required for the football to reach the highest point in its trajectory? How high does it get above the ground?How much time after it is thrown does it take to return to its original height? How far has the football traveled horizontally from its original position?
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