A football is thrown horizontally with an initial velocity of (16.5 m/s). Ignoring air resistance, the average acceleration of the football over any period of time is (-9.81 m/s2).
(a) Find the velocity vector of the ball 1.62 s after it is thrown.
(b) Find the magnitude and direction of the velocity at this time.
I started by using avg.acceleration=(Vf-Vi)/t. I calculated .375m/s. Then I realized I need ^x and ^y. How do I find that?
No, the acceleration here is downward, perpendicular to the velocity.
The veloicty keeps its initial horizontal velocity, but gains a vertical velocity.
Vvertical= acceleration*time
So add the Vvertical with Vhorizontal, to get the vector velocity.
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