The correct answer is A. y=-0.01(x-64)^2+2
In vertex form, the equation of a parabola is y = a(x-h)^2 + k, where (h,k) is the vertex of the parabola.
From the given information, we know that the vertex of the parabola is (2, 64) and the parabola opens downwards.
To find the value of a, we can use the fact that the height of the ball at time t=1 second is 48 feet.
Plugging in the values into the equation, we get:
48 = -0.01(1-64)^2 + 2
48 = -0.01(63)^2 + 2
48 = -0.01(3969) + 2
48 = -39.69 + 2
48 = -37.69
Since this equation holds true, we can conclude that the value of a is -0.01.
Therefore, the equation of the parabola in vertex form is y = -0.01(x-64)^2 + 2.
a football is punted into the air after 1 second the ball is 48 feet in the air after 2 seconds the football reaches its maximum height of 64 feet write the equation of the parabola in vertex form
A y=-0,01(x-64)^2+2
B y=(x-2)^2+64
C-16(x-2)^2+64
Dy=-2(x-1)62+48
1 answer
1 answer