Asked by Nogard
A football is punted at an angle of 44.6 with the horizontal. if it stays in the air for 3.6 seconds, what was the initial velocity of the football?
Answers
Answered by
Steve
The vertical component of the velocity is
Vy = V cos 44.6 = .712V
The height of the ball in feet is given by
h(t) = (.712V)t - 16t^2
So, if h(t) = 0 when t=3.6,
.712V*3.6 - 16*3.6^2 = 0
V = 80.9 ft/s
Guy's a pretty decent kicker, since the average kickoff speed is about 50 mph = 73 ft/s
Vy = V cos 44.6 = .712V
The height of the ball in feet is given by
h(t) = (.712V)t - 16t^2
So, if h(t) = 0 when t=3.6,
.712V*3.6 - 16*3.6^2 = 0
V = 80.9 ft/s
Guy's a pretty decent kicker, since the average kickoff speed is about 50 mph = 73 ft/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.