The vertical component of the velocity is
Vy = V cos 44.6 = .712V
The height of the ball in feet is given by
h(t) = (.712V)t - 16t^2
So, if h(t) = 0 when t=3.6,
.712V*3.6 - 16*3.6^2 = 0
V = 80.9 ft/s
Guy's a pretty decent kicker, since the average kickoff speed is about 50 mph = 73 ft/s
A football is punted at an angle of 44.6 with the horizontal. if it stays in the air for 3.6 seconds, what was the initial velocity of the football?
1 answer