A flywheel with a moment of inertia of 1.00kg m^2 is rotating at 100 rpm. What torque is required to bring it to rest in 10.0 revolutions?

Answer 1

average rpm during halt = 50 rev/min
time to halt = 10 rev/50 rev/min
= .2 min or 12 seconds

omega at start = 100 rev/min*2pi rad/rev * 1 min/60s

= 100 *2pi/60 radians/second

so alpha = d omega/dt
= - 10pi/3 / 12 radians/s^2
and
Torque = I * alpha