A flowerpot falls from a window sill 38.5 m

above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s
2
.
Answer in units of m/s.

1 answer

Use v1^2-v0^2=2aS

v1=final velocity
v0=initial velocity (0 for a free-fall)
a=acceleration due to gravity (=-9.81 m/s^2)
S=-38.5m
solve for v1.