area covered by 10 by 10 tiles = 800 x 100 or 80000 cm^2
each 8 by 8 covers 64 cm^2
so number of smaller tiles = 80000/64 = 1250 tiles
A floor is covered by 800 tiles measuring 10 cm square.How many square tiles of side 8 cm would be needed to cover the same floor?
3 answers
Square tiles = 8 × 8 = 64cm^2
Previous tiles = 10 × 10 = 100
Area covered = 100 × 800 = 80000cm^2
No of tiles = 80000÷64 = 1250 tiles
Previous tiles = 10 × 10 = 100
Area covered = 100 × 800 = 80000cm^2
No of tiles = 80000÷64 = 1250 tiles
The total area covered is 800 x 10 or 8000 cm2. The new tiles cover 8cm by 8cm, or 8 x 8 = 64 cm2. Simply divide 8000 by 64 to get the answer