weight = 50 g = 50 * 9.81 = 491 Newtons
force up = FT sin 14 = 491
so FT = 491/sin 14 = 2030 Newtons tension
horizontal component = 2030 cos 14 = 1970 Newtons
force up by pole = weight of 50 kg mass = 491 N if nothing accelerates
A floodlight with a mass of 50 kg is used to
illuminate the parking lot in front of a library.
The floodlight is supported at the end of a
horizontal beam that is hinged to a vertical
pole, as shown. A cable that makes an angle
of 14◦ with the beam is attached to the pole to
help support the floodlight. Assume the mass
of the beam is negligible when compared with
the mass of the floodlight.
1. Find the force FT provided by the cable.
The acceleration of gravity is 9.81 m/s
2. Find the horizontal force exerted on the beam
by the pole
3.Find the vertical force exerted on the beam
by the pole. Answer in units of N.
2 answers
what is vertical?
2 answers