d = 42m1[135o] - 34mi[270o]
X = 42*Cos135 = -29.7 mi
Y = 42*sin135 - 34*sin270 = 63.7 mi.
Tan A = Y/X = 63.7/-29.7 = -2.14473
A = -65o = 65o N. of W. = 115o, CCW.
d = Y/sin A = 63.7/sin 115 = 70.3 mi.
d = V*t = 70.3
V = 70.3/t = 70.3/0.5h = 140.6 mi/h
A flight controller determines that an airplane is 34.0mi south of him. Half an hour later, the same plane is 42.0mi northwest of him.
The general direction of the airplane’s velocity is?
If the plane is flying with constant velocity, what is the direction of its velocity during this time, degrees north of west?
What is the magnitude of its velocity during this time?
1 answer