(V1/n1)=(V2/n2)
(5.12÷7.51)=18.3÷n2
n2=26.84mol
A flexible container at an initial volume of 5.12 L contains 7.51 mol of gas. More gas is then added to the container until it reaches a final volume of 18.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
2 answers
1.5