A flatbed truck is carrying a 2540 kg crate of heavy machinery. If the coefficient of static friction between the crate and the bed of the truck is 0.540 , what is the maximum rate (in meters/second^2) that the driver can decelerate when coming to a stop, in order to avoid crushing the cab of the truck with the crate?

Answer 1

M*a = Max static friction force
= M*g*0.54
M cancels out
a = 0.54g = 5.29 m/s^2
(assuming the crate is not tied down)