tangential acceleration=(vf-vi)/time. So the time taken to make the curved end is PI*25/avgV
avgV=(12.4+5.9)/2
so figure out time.
now calculate the "constant" tangential acceleration.
Now, total acceleration consists of centripetal and tangential.
Acceleration=sqrt((v^2/25)^2 + tanAcc^2) where v is at the beginning 12.4, and at the end 5.9m/s.
A flat go-kart track consists of two straightways 100 m long with semicircular ends which have a radius of 25.0 m. A go-kart executes the curved end with a constant tangential acceleration while slowing from 12.4 m/s to 5.9 m/s. Determine the magnitude of the total acceleration of the go-kart at the beginning and end of the curve. (Enter your answers to at least two decimal places.)
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