A flat belt fits around a pulley which has a diameter of 45cm. The belt has a speed of 17,6m/s and transmits 9N per mm belt. The effective pull force in the belt is 423N and the belt has a width of 18cm. Calculate:

Question

a) The power transmitted by the belt in KW
b) The tight side of the force
c) pulley speed in r/s

Answer 1

a) To calculate the power transmitted by the belt, we can use the formula:

Power = (Speed of the belt) x (Tight side force)

Power = 17.6 m/s x 423 N
Power = 7456.8 W = 7.46 KW

Therefore, the power transmitted by the belt is 7.46 KW.

b) The tight side force can be calculated by dividing the total force transmitted (9 N per mm) by the width of the belt:

Tight side force = (Total force transmitted) / (Belt width)
Tight side force = 423 N / 0.18 m
Tight side force = 2350 N

Therefore, the tight side force is 2350 N.

c) The pulley speed in r/s can be calculated by first finding the circumference of the pulley using the formula:

Circumference = π x diameter
Circumference = π x 45 cm
Circumference = 141.37 cm

Now we can convert this to meters and calculate the pulley speed:

Circumference = 1.4137 meters
Pulley speed = Speed of the belt / Circumference
Pulley speed = 17.6 m/s / 1.4137 m
Pulley speed = 12.446 r/s

Therefore, the pulley speed is 12.446 r/s.