prob(both defective) = (2/8)(1/7) = 1/28
prob(at least one good) = 1 - 1/28 = 27/28
A flashlight has 8 batteries, 2 of which are defective. If you select 2 batteries, find the probability that
You select at least 1 good battery
2 answers
8c2= 28
Picking one (2c1)(6c1)=12
prob= 12/28=.43
Picking one (2c1)(6c1)=12
prob= 12/28=.43