A fixed 0.15 kg solid-disk pulley with a radius of 0.075 m is acted on by a net torque of 6.8 m·N. What is the angular acceleration of the pulley?

Answer 1

angular acceleration =
(Torque)/(Moment of inertia)

For a solid disc,
Moment of Inertia = (1/2) M R^2

The answer will be in radians/second^2