A fisherman notices that his boat is moving uo and down periodically, owing to waves on the surface of the water. It takes 2.5 s for the boat to travel from its highest point to its lowest, a total distance of 0.62 m. The fisherman sees that the wave crests are spaced 6.0 m apart. (a) How fast are the waves traveling? (b) What is the amplitude of the water? (c) If the total vertical distance traveled by the boat were 0.30 m, but the other date remained the same, how would the answers to parts (a) and (b) be affected?
6 answers
draw a sketch of the wave crests. You know wavelength, and velocity. You know amplitude. Part c requires some thinking, and we will be happy to critique your thinking.
THe problem is I don't know where to start. I need some help
Part a)
We know the formula for calculating the value of the speed of the wave traveling is:
v = fλ
= λ / T
= (6.0m) / (2.5s + 2.5s)
= (6.0m) / (5.0s) = 1.2m/s
Part c) Amplitude of the water is:
0.62m / 2 = 0.31
We know the formula for calculating the value of the speed of the wave traveling is:
v = fλ
= λ / T
= (6.0m) / (2.5s + 2.5s)
= (6.0m) / (5.0s) = 1.2m/s
Part c) Amplitude of the water is:
0.62m / 2 = 0.31
Part a)
We know the formula for calculating the value of the speed of the wave traveling is:
v = fλ
= λ / T
= (6.0m) / (2.5s + 2.5s)
= (6.0m) / (5.0s) = 1.2m/s
Part b)
Amplitude of the water is:
0.62m / 2 = 0.31
We know the formula for calculating the value of the speed of the wave traveling is:
v = fλ
= λ / T
= (6.0m) / (2.5s + 2.5s)
= (6.0m) / (5.0s) = 1.2m/s
Part b)
Amplitude of the water is:
0.62m / 2 = 0.31
may I ask how you came up with the value for the wavelength?
the wavelength is given, its the distance between two crests
0 answers