h = (t-9)^2 + 170
h is least when t = 9s
The value of h there is 170.
The vertex is therefore at
t = 9; h=170
a firework is modelled by the relation h=-4.9(t-9)^2+170 h=height above ground in metres and t=time in seconds
what are the co-ordinates of the vertex of this parabola?
2 answers
your equation
h=-4.9(t-9)^2+170
is in the standard form of the "vertex" form of a quadratic function,
the vertex is (9, 170)
[standard form ...
if y = a(x-h)^2 + k , the vertex is (h,k) ]
h=-4.9(t-9)^2+170
is in the standard form of the "vertex" form of a quadratic function,
the vertex is (9, 170)
[standard form ...
if y = a(x-h)^2 + k , the vertex is (h,k) ]
2 answers