A firework is launched into the air from ground level with an initial velocity of 128 ft/s. If acceleration due to gravity is –16 ft/s2, what is the maximum height reached by the firework?

Answer 1

recall that the height h is given by

h(t) = 128t - 16t^2

That's just your good old friend, the parabola. Find its vertex -- that is the maximum height.

Answer 2

256ft