Asked by Anonymous
A fireman tosses his 0.863-kg hat onto a peg, where it oscillates as a physical pendulum. If the center of mass of the hat is 8.32 cm from the pivot point, and its period of oscillation is 0.762 s, what is the moment of inertia of the hat about the pivot point?
Answers
Answered by
bobpursley
I= (MgDT^2)/4PI^2
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