A firefighter at street-level, 55.0 m away from a burning building, directs a stream of water from a fire hose at an angle of 35.0° above the horizontal. If the speed of the stream is 50.0 m/s, at what height will the stream of water strike the building?
I started by finding the x and y components separately:
Vox= 50cos35= 40.958 & Voy= 50sin35= 28.697. I thought that I should use:
Delta y= Voy(t) + (1/2)(9.81m/s)(t^2)
But I need time; can I find t with t= square root of 2(55)/(9.81) = 3.349sec? Is this correct?
vox= 40.9
voy= 28.7
You know horizontal distance, so solve for time
55=vox*time
Now, having time, solve for height
h= voyi*time - 1/2 g time^2
Thank you! The answer was correct.
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