According to the ideal gas law, the pressure of a gas is directly proportional to its temperature, assuming all other variables remain constant. Thus, we can use the equation P1/T1 = P2/T2 to solve this problem, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.
Given:
P1 = 13 atm
T1 = 25°C = 25 + 273.15 = 298.15 K
T2 = 79°C = 79 + 273.15 = 352.15 K
Substituting these values into the equation, we get:
P1/T1 = P2/T2
13 atm / 298.15 K = P2 / 352.15 K
Solving for P2:
P2 = (13 atm) * (352.15 K) / 298.15 K
P2 ≈ 15.36 atm
Rounding to two significant figures and including the appropriate units, the final pressure is approximately 15.36 atm.
A fire extinguisher has a pressure of 13 atm at 25 °C.
What is the final pressure, in atmospheres, when the fire extinguisher is used at a temperature of 79°C, if V and n do not change?
Express your answer to two significant figures and include the appropriate units.
1 answer
1 answer