Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
A final exam in sociology has a mean of 72 and a standard deviation of 9.2. If 35 students are randomly selected, find the probability that the mean of their test scores will be greater than 76. Round to tenth of a percent
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