Just solve for length.
L=a/w
Either that or you gave too little detail.
a figure is made up of a big square and 4 smaller identical squares. The area of the whole figure is 980 square inches. What is the unknown length?
4 answers
is there a width provided?
no width was given
side of large square --- x
side of smaller square ---- y
x^2 + 4y^2 = 980
x^2 = 980 - 4y^2
x = √(980 - 4y^2)
so 980 - 4y^2 > 0
4y^2 < 980
y^2 < 245
0 < y < appr 15.65 -----> 0 < x < appr 31.3
e.g. suppose y = 7, then x = √(980 - 4(49)) = 28
one large square of 28 by 28, and 4 smaller squares of 7 by 7
side of smaller square ---- y
x^2 + 4y^2 = 980
x^2 = 980 - 4y^2
x = √(980 - 4y^2)
so 980 - 4y^2 > 0
4y^2 < 980
y^2 < 245
0 < y < appr 15.65 -----> 0 < x < appr 31.3
e.g. suppose y = 7, then x = √(980 - 4(49)) = 28
one large square of 28 by 28, and 4 smaller squares of 7 by 7
1 answer