the plane and the shell cover the same horizontal distance in time t
T = angle up from horizontal
u = 1100 cos T = 600,000/3600 m/s
so T = 81.3 degrees
so Vi = initial speed up = 1100sin 81.3
= 1087 m/s up
how long to reach 2500 meters high?
2500 = 1087 t - 4.9 t^2
4.9 t^2 + 1087 t - 2500 = 0
solve for t, use + result
d = u t
A fighter plane is directly over an anti aircraft gun at a time t=0. The plane has a speed of 600km/hr. A shell is fired from an anti aircraft gun at the time t=0, in order to hit the plane. The muzzle velocity V is 1100m/s. Determine the distance the gun should be aimed ahead of the plane in order to hit it if the distance of the plane from the ground is 2500m.
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