A fighter pilot dives his plane toward the ground at 345 m/s. He pulls out of the dive on a vertical circle. What is the minimum radius of the circle, so that the normal force exerted on the pilot by his seat never exceeds three times his weight?

Answer 1

3mg>mv^2/r

solve for r

Answer 2

my answer was wrong.. I got 4048.47? What did you get?

Answer 3

oops. Normal force on his seat includes his weight.

3mg>mg+mv^2/r

Answer 4

So then... once you divide out the m's it would be 3g>g+v^2/r?

Answer 5

yes.