boat north rel to water = 4.4 sin 28
boat east rel to water = 4.4 cos 28
pass north rel to water = 4.4 sin 28 same as boat = 2.07
pass east rel to water = 4.4 cos 28 + 2.2 = 3.88 + 2.2 = 6.08
mag = sqrt (2.07^2 + 6.08^2)
tan angle N of E = 2.07/6.08
a ferryboat is travelling in a direction of 28 degrees north of east with a speed of 4.40 m/s relative to the water. A passenger is walking with a velocity of 2.20 m/s due east relative to the boat. What is the magnitude and direction of the velocity of the passenger with respect to the water. Give directional Angle to due east.
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