X = Hor. = 2.4 m/s.
Y = Ver. = 1.7 m/s.
a. Vb^2 = X^2 + Y^2.
Vb^2 = 5.76 + 2.89 = 8.65
Vb = 2.94 m/s. = Velocity of boat.
b. tanA = Y/X = 1.7/2.4 = 0.70833
A = 35.3o,CCW.
A ferry is crossing a river. The ferry is headed
due north with a speed of 1.7 m/s relative to
the water and the river’s velocity is 2.4 m/s
to the east.
a) What is magnitude of the boat’s velocity
relative to Earth?
Answer in units of m/s
b) Find the direction in which the ferry is
moving (measured from due east, with counterclockwise positive).
Answer in units of
◦
1 answer
1 answer