A Ferris wheel with radius 9.8 m rotates at a constant rate, completing one revolution every 36.6 s. Suppose the Ferris wheel begins to decelerate at the rate of 0.227 rad/s2 when a passenger is at the top of the wheel. Find the magnitude and direction of the passenger's acceleration at that time.

Question

_____magnitude

direction______° below direction of travel

Answer 1

first find angular speed
w=(2pi)/36.6 to get rad/s
then, you must find a(cp) and a(tangential)
acp=r*w2
at=r*alpha =>9.8*-.227
use a=sqrt(acp^2+at^2)
the answer is the magnitude

to find the angle use tan^-1(acp/at)