A Ferris wheel with radius 14.0 m
is turning about a horizontal axis through
its center as shown in the figure. The linear speed of a
passenger on the rim is constant and equal to 7.0 m/s. What are the
magnitude and direction of the passenger's acceleration as she
passes through (a) the lowest point in her circular motion? (b) The
highest point in her circular motion? (c) How much time does it
take the Ferris wheel to make one revolution?.
2 answers
9.9
a= v^2/r
= 7.0m/s/14.0m
a= 3.5 m/s^2
(a) 3.5m/s^2 upwards
(b) 3.5m/s^2 downwards
(c) T= 2pi*r/v
= 2pi*14.0m/7.0m/s
T= 12.6s
= 7.0m/s/14.0m
a= 3.5 m/s^2
(a) 3.5m/s^2 upwards
(b) 3.5m/s^2 downwards
(c) T= 2pi*r/v
= 2pi*14.0m/7.0m/s
T= 12.6s